Listen Sie auf, welche Spalten in SQL Server 2005 einen Volltextindex haben

select distinct
    object_name(fic.[object_id]) table_name,
    [name] column_name
from
    sys.fulltext_index_columns fic
    inner join sys.columns c
        on c.[object_id] = fic.[object_id]
        and c.[column_id] = fic.[column_id]