Probieren Sie dieses Beispiel aus, das Ihnen die Ausgabe (1 Beispielzeile) gibt
id Name ParentID Path abbreviation (No column name)
5 China 2 Asia/China CN,AS Asia/China:CN,AS
Das TSQL-Wesen
DECLARE @tbl TABLE (
Id INT
,[Name] VARCHAR(20)
,ParentId INT
)
INSERT INTO @tbl( Id, Name, ParentId )
VALUES
(1, 'Europe', NULL)
,(2, 'Asia', NULL)
,(3, 'Germany', 1)
,(4, 'UK', 1)
,(5, 'China', 2)
,(6, 'India', 2)
,(7, 'Scotland', 4)
,(8, 'Edinburgh', 7)
,(9, 'Leith', 8)
;
DECLARE @tbl2 table (id int, abbreviation varchar(10), tbl_id int)
INSERT INTO @tbl2( Id, Abbreviation, tbl_id )
VALUES
(100, 'EU', 1)
,(101, 'AS', 2)
,(102, 'DE', 3)
,(103, 'CN', 5)
;WITH abbr AS (
SELECT a.*, isnull(b.abbreviation,'') abbreviation
FROM @tbl a
left join @tbl2 b on a.Id = b.tbl_id
), abcd AS (
-- anchor
SELECT id, [Name], ParentID,
CAST(([Name]) AS VARCHAR(1000)) [Path],
cast(abbreviation as varchar(max)) abbreviation
FROM abbr
WHERE ParentId IS NULL
UNION ALL
--recursive member
SELECT t.id, t.[Name], t.ParentID,
CAST((a.path + '/' + t.Name) AS VARCHAR(1000)) [Path],
isnull(nullif(t.abbreviation,'')+',', '') + a.abbreviation
FROM abbr AS t
JOIN abcd AS a
ON t.ParentId = a.id
)
SELECT *, [Path] + ':' + abbreviation
FROM abcd
