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Funktion String in Dezimalzahlen aufteilen?

Dies ist eine generische Funktion, um eine beliebige Textzeichenfolge in eine Wertetabelle zu zerlegen ... Sie können sie einfach verwenden, um das zu tun, was Sie erreichen möchten:

ALTER FUNCTION [dbo].[ParseTextString] (@S Text, @delim VarChar(5))
Returns @tOut Table 
    (ValNum Integer Identity Primary Key, 
     sVal VarChar(8000))
As
Begin 
Declare @dLLen TinyInt       -- Length of delimiter
Declare @sWin  VarChar(8000) -- Will Contain Window into text string
Declare @wLen  Integer       -- Length of Window
Declare @wLast TinyInt     -- Boolean to indicate processing Last Window
Declare @wPos  Integer     -- Start Position of Window within Text String
Declare @sVal  VarChar(8000) -- String Data to insert into output Table
Declare @BtchSiz Integer     -- Maximum Size of Window
    Set @BtchSiz = 7900      -- (Reset to smaller values to test routine)
Declare @dPos Integer        -- Position within Window of next Delimiter
Declare @Strt Integer        -- Start Position of each data value within Window
-- -------------------------------------------------------------------------
If @delim is Null Set @delim = '|'
If DataLength(@S) = 0 Or
      Substring(@S, 1, @BtchSiz) = @delim Return
-- ---------------------------
Select @dLLen = Len(@delim),
       @Strt = 1, @wPos = 1,
       @sWin = Substring(@S, 1, @BtchSiz)
Select @wLen = Len(@sWin),
       @wLast = Case When Len(@sWin) = @BtchSiz
           Then 0 Else 1 End,
       @dPos = CharIndex(@delim, @sWin, @Strt)
-- ------------------------------------
  While @Strt <= @wLen
  Begin
      If @dPos = 0 -- No More delimiters in window
      Begin                      
          If @wLast = 1 Set @dPos = @wLen + 1 
          Else 
          Begin
              Set @wPos = @wPos + @Strt - 1
              Set @sWin = Substring(@S, @wPos, @BtchSiz)
              -- ----------------------------------------
              Select @wLen = Len(@sWin), @Strt = 1,
                     @wLast = Case When Len(@sWin) = @BtchSiz
                              Then 0 Else 1 End,
                     @dPos = CharIndex(@delim, @sWin, 1)
              If @dPos = 0 Set @dPos = @wLen + 1 
          End
      End
      -- -------------------------------
      Set @sVal = LTrim(Substring(@sWin, @Strt, @dPos - @Strt))
      Insert @tOut (sVal) Values (@sVal)
      -- -------------------------------
      -- Move @Strt to char after last delimiter
      Set @Strt = @dPos + @dLLen 
      Set @dPos = CharIndex(@delim, @sWin, @Strt)
   End
   Return
End