Verwenden Sie dazu einen JOIN gegen eine Unterauswahl, um die höchste ID aus my_rel_table
zu erhaltenDELETE my_rel_table, my_photo_table
FROM my_rel_table
INNER JOIN
(
SELECT MAX(id) AS MaxId
FROM my_rel_table
WHERE relid = 1
AND type = 1
) Sub1
ON my_rel_table.id = Sub1.MaxId
LEFT OUTER JOIN my_photo_table ON my_photo_table.typeid = my_rel_table.typeid
WHERE my_rel_table.relid = 1
AND my_rel_table.type = 1
Nicht direkt getestet, da ich keine Testdaten habe!
BEARBEITEN - Ein paar Versuche, die Top 5 zu schaffen, aber wieder nicht getestet
DELETE my_rel_table, my_photo_table
FROM my_rel_table
INNER JOIN
(
SELECT id
FROM my_rel_table
WHERE relid = 1
AND type = 1
ORDER BY id DESC
LIMIT 5
) Sub1
ON my_rel_table.id = Sub1.id
LEFT OUTER JOIN my_photo_table ON my_photo_table.typeid = my_rel_table.typeid
WHERE my_rel_table.relid = 1
AND my_rel_table.type = 1
Oder anders.
DELETE my_rel_table, my_photo_table
FROM my_rel_table
INNER JOIN
(
SELECT id, @Counter:[email protected]+1 AS ItemCounter
FROM my_rel_table
CROSS JOIN (SELECT @Counter:=0) Sub1
WHERE relid = 1
AND type = 1
ORDER BY id DESC
) Sub1
ON my_rel_table.id = Sub1.id
AND Sub1.ItemCounter <= 5
LEFT OUTER JOIN my_photo_table ON my_photo_table.typeid = my_rel_table.typeid
WHERE my_rel_table.relid = 1
AND my_rel_table.type = 1