Sie können die folgende Abfrage für Ihren erwarteten Ergebnissatz verwenden
SELECT *,
COALESCE(
(SELECT SUM(pt.rupees) FROM (
SELECT MONTH(`date`) `month`,
MAX(id) id,
SUM(rupees) rupees
FROM house_details
GROUP BY `month`,subincome
) pt
WHERE CASE WHEN pt.month = t1.month THEN pt.id < t1.id ELSE pt.month < t1.month END
), 0) AS progressive_total,
(SELECT SUM(rupees) FROM(
SELECT MONTH(`date`) `month`,
MAX(id) id,
SUM(rupees) rupees
FROM house_details
GROUP BY `month`,subincome
) cs
WHERE CASE WHEN cs.month = t1.month THEN cs.id <= t1.id ELSE cs.month <= t1.month END
) AS cumulative_sum
FROM (
SELECT MONTHNAME(t.date) AS `monthname`,
MAX(id) id,
MONTH(t.date) `month`,
YEAR(t.date) AS `year`,
GROUP_CONCAT(t.income) income,
t.subincome,
GROUP_CONCAT(t.ssubincome) ssubincome,
SUM(rupees) AS amount,
GROUP_CONCAT(receipt_id) AS receipt_ids
FROM house_details t
WHERE YEAR(t.date) = YEAR(CURRENT_DATE())
GROUP BY `monthname`,`month`, t.subincome
ORDER BY `month`
) t1
