Versuchen Sie Folgendes:
SELECT DISTINCT(l.name) AS link
FROM links l INNER JOIN tags t ON l.id = t.link_id
AND l.id <> 1 GROUP BY t.link_id ORDER BY COUNT(t.link_id) DESC
Versuchen Sie Folgendes:
SELECT DISTINCT(l.name) AS link
FROM links l INNER JOIN tags t ON l.id = t.link_id
AND l.id <> 1 GROUP BY t.link_id ORDER BY COUNT(t.link_id) DESC