Wenn Sie Funktionen wie count, sum usw. verwenden, müssen Sie eine group by-Klausel hinzufügen, um die Gruppierung der Ergebnisse zu steuern:
select
concat(u.first_name, ' ', u.last_name) as name,
u.skill,
ut.name as team_name,
(count(if(a.tech_id = u.user_id AND a.qc_id = 0 AND a.status = 2,1,0))) AS assigned_scopes,
(count(if(a.tech_id = u.user_id AND a.qc_id > 0 AND a.status = 3,1,0))) AS assigned_qa,
(count(if(a.assignment_id=o.assignment_id and a.tech_id = u.user_id AND a.status = 2 AND a.qc_id = 0 and o.class_id= 3,1,0))) AS assigned_canvass,
from am_ts_order o
left join am_ts_assignment a
ON a.assignment_id=o.assignment_id
left join am_user u
ON a.tech_id=u.user_id
left join user_team ut
ON u.user_team_id = ut.user_team_id
where u.user_role_id = 15
and u.user_team_id = ut.user_team_id
order by u.first_name asc
group by a.tech_id
AKTUALISIERUNG:
Diese Abfrage ändert die IF-Bedingungen, um zu testen, ob in einigen der links verknüpften Tabellen eine übereinstimmende Zeile gefunden wurde:
select
concat(u.first_name, ' ', u.last_name) as name,
u.skill,
ut.name as team_name,
count(if(
(NOT a.tech_id IS NULL) AND
(NOT u.user_id IS NULL) AND
a.qc_id = 0 AND
a.status = 2,1,0)) AS assigned_scopes,
count(if(
(NOT a.tech_id IS NULL) AND
a.qc_id > 0 AND
a.status = 3,1,0)) AS assigned_qa,
count(if(
(NOT a.assignment_id IS NULL) AND
a.assignment_id = o.assignment_id AND
a.tech_id = u.user_id AND
a.status = 2 AND
a.qc_id = 0 AND
o.class_id= 3,1,0)) AS assigned_canvass,
from am_ts_order o
left join am_ts_assignment a
ON a.assignment_id=o.assignment_id
left join am_user u
ON a.tech_id=u.user_id
left join user_team ut
ON u.user_team_id = ut.user_team_id
where u.user_role_id = 15
and u.user_team_id = ut.user_team_id
order by u.first_name asc
group by a.tech_id
