DECLARE @t TABLE (
TransNo VARCHAR(20),
Serial INT,
Project INT
)
INSERT INTO @t (TransNo, Serial, Project)
VALUES
('A00000000000001', 1, 100),
('A00000000000001', 2, 200),
('A00000000000001', 3, 201),
('A00000000000001', 4, 101),
('A00000000000002', 1, 100),
('A00000000000002', 2, 101),
('A00000000000003', 1, 100),
('A00000000000003', 2, 200),
('A00000000000004', 1, 200),
('A00000000000004', 2, 100),
('A00000000000005', 1, 101),
('A00000000000005', 2, 100)
SELECT *, CProject = (
SELECT DISTINCT [text()] = t2.Project
FROM @t t2
WHERE t2.TransNo = t1.TransNo
ORDER BY t2.Project
FOR XML PATH('')
)
FROM @t t1
Ausgabe -
TransNo Serial Project CProject
-------------------- ----------- ----------- --------------
A00000000000001 1 100 100101200201
A00000000000001 2 200 100101200201
A00000000000001 3 201 100101200201
A00000000000001 4 101 100101200201
A00000000000002 1 100 100101
A00000000000002 2 101 100101
A00000000000003 1 100 100200
A00000000000003 2 200 100200
A00000000000004 1 200 100200
A00000000000004 2 100 100200
A00000000000005 1 101 100101
A00000000000005 2 100 100101
mit [text()] -
100101200201
ohne [text()] -
<Project>100</Project><Project>101</Project><Project>200</Project><Project>201</Project>
mehr Details - http:// www.codeproject.com/Articles/691102/String-Aggregation-in-the-World-of-SQL-Server
aktualisieren -
SELECT *, CProject = (
SELECT [text()] = t2.Project
FROM (
SELECT t2.Project, Serial = MIN(t2.Serial)
FROM @t t2
WHERE t2.TransNo = t1.TransNo
GROUP BY t2.Project
) t2
ORDER BY t2.Serial
FOR XML PATH('')
)
FROM @t t1
