Versuchen Sie, Binds-Variablen und vorbereitete Anweisungen zu verwenden:
<?php
$mysqli = new mysqli("localhost", "user", "pass", "db");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
if (isset($_POST['scriptname'])) {
$scriptname = $_POST['scriptname'];
$stmt = $mysqli->prepare("INSERT INTO appslist(listall) VALUES (?)");
$stmt->bind_param('s', $scriptname);
/* execute prepared statement */
$stmt->execute();
printf("%d Row inserted.\n", $stmt->affected_rows);
/* close statement and connection */
$stmt->close();
}
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
Script Name: <input type="text" name="scriptname">
<input type="submit">
</form>
Ausgabe:
1 Row inserted.
http://php.net/manual/en/mysqli.quickstart .prepared-statements.php
