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Wie kann man nach Monat gruppieren und Null zurückgeben, wenn für einen bestimmten Monat kein Wert vorhanden ist?

Haben Sie eine Tabelle mit allen Monaten und dann left join zu Ihrem Tisch:

SELECT MONTHNAME(m.month) AS mName, 
    MONTH(m.month) AS mOrder, 
    ifnull(sum(amount),0) AS total_num 
from months m
left join income i
on m.month = i.date

GROUP BY mOrder 
ORDER BY mOrder DESC

Wenn Sie keine months erstellen möchten Tabelle dann können Sie:

(select STR_TO_DATE('01/01/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/02/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/03/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/04/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/05/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/06/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/07/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/08/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/09/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/10/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/11/2016', '%d/%m/%Y') as month union 
 select STR_TO_DATE('01/12/2016', '%d/%m/%Y') as month)