Ich kannte die Funktion find_in_set() nicht und habe einen handwerklicheren Ansatz gewählt. Nicht, dass es angesichts der ersten Antwort Sinn macht, aber ich werde es trotzdem posten:
SELECT id
FROM (
SELECT '757392' AS id UNION
SELECT '733602' UNION
SELECT '749955' UNION
SELECT '744304' UNION
SELECT '746852' UNION
SELECT '753904' UNION
SELECT '755117' UNION
SELECT '636163' UNION
SELECT '564931' UNION
SELECT '740787' UNION
SELECT '751450' UNION
SELECT '743799' UNION
SELECT '643918' UNION
SELECT '749903' UNION
SELECT '571888' UNION
SELECT '30207' UNION
SELECT '705953' UNION
SELECT '749120' UNION
SELECT '749001' UNION
SELECT '749192' UNION
SELECT '749978' UNION
SELECT '750840' UNION
SELECT '544228' UNION
SELECT '702121' UNION
SELECT '746246' UNION
SELECT '383667' UNION
SELECT '558790' UNION
SELECT '585628' UNION
SELECT '592771' UNION
SELECT '745818' UNION
SELECT '749375' UNION
SELECT '241209' UNION
SELECT '749235' UNION
SELECT '746860' UNION
SELECT '748318' UNION
SELECT '748016' UNION
SELECT '748951' UNION
SELECT '747321' UNION
SELECT '748684' UNION
SELECT '748225' UNION
SELECT '565375' UNION
SELECT '748673' UNION
SELECT '747869' UNION
SELECT '748522' UNION
SELECT '748335' UNION
SELECT '744775' UNION
SELECT '672229' UNION
SELECT '578056' UNION
SELECT '713127' UNION
SELECT '740234' UNION
SELECT '632608' UNION
SELECT '711135' UNION
SELECT '746528' UNION
SELECT '362131' UNION
SELECT '742223' UNION
SELECT '746567' UNION
SELECT '745224' UNION
SELECT '332989' UNION
SELECT '439837' UNION
SELECT '745418' UNION
SELECT '673582' UNION
SELECT '269584' UNION
SELECT '742606' UNION
SELECT '745135' UNION
SELECT '746950' UNION
SELECT '476134' UNION
SELECT '740830' UNION
SELECT '742949' UNION
SELECT '276934') AS id_list
WHERE id NOT IN (
SELECT id
FROM users);
